Question

10g of $NaOH$ required a certain amount of $H_{2}S{O}_4$ for complete neutralization. Calculate the amount of $H_{2}S{O}_4$ required.

• A. 10 g
• B. 12.25 g
• C. 24.5 g
• D. 49 g

Answer 1

Answer: (B)

12.25 g

The balanced equation for the neutralisation reaction is :

$2NaOH+H_{2}S{O}_4\to N{a}_{2}S{O}_4+2H_{2}O$

40g of NaOH requires = $\frac{98}{2}$g of $H_{2}S{O}_4$

10g of NaOH requires = $\frac{98\times 10}{2\times 40}$ = 12.25g of $H_{2}S{O}_4$