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Question

10lm is one of the factors of 20l2m+30alm.
The other factor is


A

5l+3m

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B

2l+3a

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C

3l+2m

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D

3l+2a

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Solution

The correct option is B

2l+3a


Given, one of the factors of 20l2m+30alm is 10lm.

Hence,
20l2m+30alm
=10lm (20l2m10lm+30alm10lm)
=10lm (2l+3a)
Hence the common factor is 2l+3a


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