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Question

10lm is one of the factors of 20l2m+30alm.
The other factor is:


A

5l + 3m

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B

2l + 3a

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C

3l + 2m

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D

3l + 2a

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Solution

The correct option is B

2l + 3a


Given 20l2m+30alm

= 10(2l2m+3alm) [Taking 10 common]
= 10lm (2l + 3a) (Taking lm common)

Hence (2l + 3a) is the other factor


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