10x when divided by 13 remainder = -1. If x is a natural number less than 100 how many solutions are possible for x ?
The first power of 10 for which a division by 13 gives a remainder -1 is x=3. the next power of 10 will be 109. hence it falls in an AP with first term as 3 and last term as 99 with a common difference of 6
number of terms = (99-3)/6 +1= 96/6 +1 = 16 +1 = 17 terms.