Question

11.2 L of a gas at STP weighs 14 g. The gas could be:

• A. $N_{2}O$
• B. $N{O}_2$
• C. $N_2$
• D. $CO$

Answer 1

Answer: (C)

$N_2$

Given mass $=14$ g

No. of moles of that gas $=\frac{11.2}{22.4}=\frac{1}{2}$ mole

We know that,

Number of moles $=\frac{\text{Given mass}}{\text{Molecular mass}}$

$\frac{1}{2}=\frac{14}{M.M.}$

Molar mass $=28$ g

Hence, the gas is Nitrogen.

Therefore, option C is correct.