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Empirical & Molecular Formula

11.2 l of a g...

Question

$11.2 l$ of a gas contains $24 g$ of gas at STP. Molecular weight of gas is _________.

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Solution

$1 m o l e$ of gas occupies $22.4 l$ at STP. So given gas has $11.2 / 22.4 = 0.5$ moles present. $0.5$ moles have a weight of $24 g$ . So, the molecular weight of gas is $24 / 0.5 = 48$ .

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