Question

11.2 litre of a gas at STP weighs 14 g. The gas could not be:

• A. $N_2$
• B. $CO$
• C. $B_2{H}_6$
• D. $N_{2}O$

Answer 1

The correct option is D

$N_{2}O$

At S.T.P 1 mole of gas occupies 22.4L of volume.

Molar mass of $N_2$, $CO$ and $B_2{H}_6$ is 28. Hence [$\frac{28}{2}=14g$] of these compounds occupies the volume of 11.2L.
But molar mass of $N_{2}O$ is 44g, 22g of it is a half mole which occupies 11.2L of volume.