1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Summation by Sigma Method
11, 26, 56, 1...
Question
11
,
26
,
56
,
101
,
161
,
.
.
.
.
.
A
236
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
226
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
216
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
206
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
A
236
Add
15
,
30
,
45
,
60
,
75
to each number Next number is
161
+
75
=
236
Suggest Corrections
0
Similar questions
Q.
The equation of the hyperbola
4
x
2
−
32
x
−
y
2
−
4
y
+
24
=
0
in its standard form is
Q.
What is the equation of a curve given by the parametric form
x
=
9
+
6
s
e
c
θ
;
y
=
−
2
−
4
t
a
n
θ
.
Q.
Th number of
α
a
n
d
β
−
−
emitted during the radioactive decay chain starting from
226
88
R
s
and ending at
206
82
P
b
us
Q.
The number of
α
and
β
−
emitted during the radioactive decay chain starting from
226
88
R
a
and endjg at
206
82
P
b
is
Q.
Find the Q-value and the kinetic energy of the emitted
α
-
P
article in the
α
-decay of (a)
220
86
R
n
and (b)
226
88
R
a
.
Given:
m
(
226
88
R
a
)
=
226.02540
u
,
m
(
222
86
R
n
)
=
222.01750
u
,
m
(
216
84
P
o
)
=
216.00189
u
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Summation by Sigma Method
MATHEMATICS
Watch in App
Explore more
Summation by Sigma Method
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app