-11/6 +-3/4+5/8+-7/3 find tr sum

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Solution

Dear student
$- \frac{11}{6} + (- \frac{3}{4}) + \frac{5}{8} + (- \frac{7}{3}) = - \frac{11}{6} - \frac{3}{4} + \frac{5}{8} - \frac{7}{3} = \frac{- 44 - 18 + 15 - 56}{24} = - \frac{103}{24}$
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Similar questions

\frac{5}{6}

\frac{11}{13}

\frac{4}{7}

\frac{- 3}{5}

\frac{- 7}{4}

\frac{- 3}{7}

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

x	$1$	$2$	$3$	$4$	$5$	$6$	$7$	$8$
f	$9$	$11$	$5$	$6$	$8$	$1$	$3$	$7$

Find the product

(1) 4 ⊗₅ 3

(2) 5 ⊗₇ 8

(3) (4 ⊗₁₁ 3) ⊗₁₁ 7

(4) (5 ⊗₁₂ 2) ⊗₁₂ 6

\frac{3}{7} + (\frac{- 6}{11}) + (\frac{- 8}{21}) + (\frac{5}{22})

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