11. Caesium and chloride ions are in contact along body diagonal in body centered cubic lattice .the edge length of unit cell is 350pm and Cs has a radius of 133 .hence radius of cl ion is

Open in App

Solution

Suggest Corrections

Similar questions

Q. Cesium chloride forms a body-centered cubic lattice. Cesium and chloride ions are in contact along the body diagonal of the unit cell. The length of the side of the unit cell is

412

pm and

C l^{-}

ion has a radius of

181

pm. Calculate the radius (in pm) of

C s^{+}

ion.

Q. In

C s C l

structure, cesium and chloride ions are in contact along the body diagonal of the unit cell. The length of the side of the unit cell is

412

pm and chloride ion has a radius of

181

pm. Calculate the radius (in pm) of caesium ion.

$N H_{4} C l$ crystallizes in a body-centered cubic lattice with an edge length of unit cell equal to 387 pm. If the radius of the $C l^{-}$ ion is 181 pm, the radius for $N H_{4}^{+}$ ion is?

$N H_{4} C l$ crystallizes in a body-centered cubic lattice with edge length of unit cell equal to 387 pm. If the radius of the $C l^{-}$ ion is 181 pm, radius for $N H_{4}^{+}$ ion is

$N H_{4} C l$ crystallizes in a body-centered cubic lattice with an edge length of unit cell equal to 387 pm. If the radius of the $C l^{-}$ ion is 181 pm, the radius for $N H_{4}^{+}$ ion is?

Join BYJU'S Learning Program