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Byju's Answer
Standard IX
Physics
Electric Potential and Potential Difference
(11) Calculat...
Question
(11) Calculate the cell potential of a galvanic cell whose cell representation is:
Mg
(s)
| Mg
2+
(0.1 M) || Cu
2+
(0.01 M) | Cu
(s)
. Given that E
0
Mg2+/Mg
= - 2.36V, E
0
Cu2+/Cu
= 0.34 V.
Open in App
Solution
Dear Student,
The net cell reaction :
M
g
+
C
u
2
+
(
0
.
01
M
)
→
M
g
2
+
(
0
.
1
M
)
+
C
u
A
p
p
l
y
i
n
g
t
h
e
n
e
r
n
s
t
e
q
u
a
t
i
o
n
:
E
c
e
l
l
=
E
c
e
l
l
o
-
0
.
0591
n
log
[
M
g
2
+
]
[
C
u
2
+
]
=
{
0
.
34
-
(
-
2
.
36
)
}
-
0
.
059
2
log
0
.
1
0
.
01
=
(
2
.
70
)
-
0
.
03
log
100
=
2
.
70
-
0
.
06
=
2
.
64
V
So, the potential of the galvanic cell = 2.64 V
Regards.
Suggest Corrections
1
Similar questions
Q.
a. Calculate e.m.f of cell for the reaction:
M
g
(
s
)
+
C
u
2
+
(
0.0001
M
)
→
M
g
2
+
(
0.001
M
)
+
C
u
(
s
)
Given that:
E
o
M
g
2
+
/
M
g
=
−
2.37
V
E
o
C
u
2
+
/
C
u
=
+
0.34
V
b. i) State Kohlrausch law.
ii) What is meant by limiting molar conductance.
Q.
M
g
2
+
+
2
e
−
→
M
g
;
E
∘
c
e
l
l
(
V
)
=
−
2.37
C
u
2
+
+
2
e
−
→
C
u
;
E
∘
c
e
l
l
=
0.34
Analyze the data above.
Which substance should be used for electrode B in this galvanic cell?
Q.
Calculate the reduction potential for the following half cell at
25
o
C
.
C
u
(
s
)
|
C
u
2
+
(
a
q
,
0.2
M
)
;
E
0
C
u
2
+
/
C
u
=
0.34
V
Take :
[
l
o
g
10
5
=
0.7
]
Q.
Calculate the e.m.f of the following cell reaction at
298
K
:
M
g
(
s
)
+
C
u
2
+
(
0.0001
M
)
→
M
g
2
+
(
0.001
M
)
+
C
u
(
s
)
The standard potential
(
E
o
)
of teh cell is
2.71
V
.
Q.
Calculate the emf of the cell.
Z
n
|
Z
n
2
+
(
0.001
M
)
|
|
C
u
2
+
(
0.1
M
)
|
C
u
The standard potential of
C
u
/
C
u
2
+
half-cell is +0.34 and
Z
n
/
Z
n
2
+
is -0.76 V.
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