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Question

(11) Calculate the cell potential of a galvanic cell whose cell representation is:
Mg(s) | Mg2+(0.1 M) || Cu2+(0.01 M) | Cu(s). Given that E0Mg2+/Mg = - 2.36V, E0Cu2+/Cu = 0.34 V.

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Solution

Dear Student,

The net cell reaction :
Mg + Cu2+ (0.01 M)Mg2+ (0.1M)+ CuApplying the nernst equation : Ecell = Ecello- 0.0591nlog[Mg2+][Cu2+] = { 0.34 - ( - 2.36) } - 0.0592log 0.10.01 = ( 2.70) - 0.03 log100 = 2.70 - 0.06 =2.64 V

So, the potential of the galvanic cell = 2.64 V

Regards.

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