Question

11 gm MNPQ, MP=3.8 cm , NQ=4.5 cm and angle between MP and NQ is ${60}^{\circ }$.

Answer 1

We know that, the diagonals of a parallelogram bisect one another at common point O, and equal angles are formed. Sum of all $\angle S$ around $=0={360}^o$

$x+x+x+x=360$

$4x=360$

$x=90$.