110 J of heat is added to a gaseous system, whose internal energy change is 40 J, then the amount of external work done is

150 J

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70 J

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110 J

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40 J

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Solution

The correct option is B 70 J
$Δ Q = Δ U + Δ W \Rightarrow 110 = 40 + Δ W = 70 J$

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