Question

$110J$ of heat is added to a gaseous system, whose internal energy change is $40J$, then the among work done is

• A. $150J$
• B. $70J$
• C. $110J$
• D. $40J$

Answer 1

The correct option is B $70J$

Given,

$\begin{array}{c}\Delta Q=110\\ \Delta u=40\\ \therefore \Delta w=110-40\\ =70J\end{array}$

$|therefore$ Option $B$ is correct.