Question

$110\text{g}$ of $C{O}_2$ contains:

• A. $18.26\times {10}^{23}$ molecules of $C{O}_2$
• B. $12.04\times {10}^{22}$ molecules of $C{O}_2$
• C. $15.05\times {10}^{23}$ molecules of $C{O}_2$
• D. None of these

Answer 1

The correct option is C $15.05\times {10}^{23}$ molecules of $C{O}_2$

Gram molecular mass of $C{O}_2=44\text{g}$
Number of moles in 110 g of $C{O}_2=\frac{110}{44}=2.5$
One mole of $C{O}_2$ contain $=6.023\times {10}^{23}$ molecules.
Therefore, $2.5$moles of $C{O}_2$ contain $6.023\times {10}^{23}\times 2.5=15.05\times {10}^{23}$ molecules.