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Standard X
Chemistry
Molecular Mass
112 cm3 of a ...
Question

112cm3 of a gaseous fluoride of phosphorus has a mass of 0.63 g. Calculate the relative molecular mass of the fluoride. If the molecule of the fluoride contains only one atom of phosphorus, then determine the formula of the phosphorus fluoride.
[F = 19; P = 31].

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Solution

1 space m o l e space o f space g a s space o c c u p i e s space v o l u m e equals 22.4 space l i t r e 112 space c m cubed space o f space g a s e o u s space f l o u r i d e space h a s space m a s s space equals 0.63 g S o comma space 22400 c m to the power of blank space w i l l space h a v e space m a s s space equals 0.63 cross times 22400 over 12 equals 126 g T h e space m o l e c u l a r space m a s s space equals A t. space m a s s space o f space P plus A t. space m a s s space o f space F 126 equals 31 plus space A t. space m a s s space o f space F s o space A t. space m a s s space o f space F space equals 95 g B u t comma space A t. space m a s s space o f space F equals 19 s o space 95 divided by 19 equals 5 H e n c e comma space t h e r e space a r e space 5 space a t o n m s space o f space F space s o space t h e space m o l e c u l a r space f o r u l a space equals P F subscript 5 space

In line 3 , use 112 cm3 instead of 12 cm3 i.e 0.63×22400112 = 126 g


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