Question

$112\text{c}{\text{m}}^{\text{3}}$ of hydrogen gas at STP contains:

• A. 0.01 mole
• B. 0.5 mole
• C. 0.005 mole
• D. 0.02 mole

Answer 1

The correct option is C 0.005 mole

At $STP,T=273K,P=1atm$

$V=112c{m}^3=112ml=0.112L$

$\therefore PV=nRT$

$\therefore n=\frac{PV}{RT}=\frac{1\times 0.112}{0.0821\times 273}=0.005$ moles

$\therefore 112c{m}^3$ of hydrogen gas at $STP$ contains $0.005$ moles

Hence, option C is correct.