$1120 m l$ of ozonised oxygen $(O_{2} + O_{3})$ at $1 a t m$ & $273 K$ weighs $1.76 g m$ . Find the reduction in volume on passing this through alkaline pyrogallol solution is:

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Solution

Molecular weight (or) mass of oxygen $= 32$
Molecular weight (or) mass of ozone $= 48$
Volume of ozonised oxygen $= 1120$ ml
Assume volume of oxygen $= x$ ml
volume of ozone $= 1120 - x$ ml
at $S T P$ (standard temperature and pressure).
Weight of $x$ ml of $O_{2} = \frac{32 x}{22400}$
weight of $1120 - x$ ml of $O_{3} = \frac{48 (1120 - x)}{22400}$
hence, $\frac{32 x}{22400} + \frac{48 (1120 - x)}{22400} = 1.76$
$\Rightarrow x = \frac{14336}{16} = 896$ ml.
$∴$ Reduction in volume on passing the mixture through alkaline pyrogallol solution is $896$ ml.

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1120 ml of ozonised oxygen (O2+O3) at 1 atm & 273 K weighs 1.76 gm. Find the reduction in volume on passing this through alkaline pyrogallol solution is:

$1120 m l$ of ozonised oxygen $(O_{2} + O_{3})$ at $1 a t m$ & $273 K$ weighs $1.76 g m$ . Find the reduction in volume on passing this through alkaline pyrogallol solution is: