Question

112ml of oxygen at STP is subjected to liquefication . The mass of liquid oxygen obtained is??

Answer 1

At STP, 22400 ml is occupied by 1 mole of a gas.
So, 112 ml will be occupied by 112/22400 = 0.005 moles of Oxygen gas

Weight of 0.005 moles of oxygen = 32 x 0.005
= 0.16 g

Weight of 112 mL of oxygen at STP on liquification would be same as weight of 0.005 moles of oxygen gas.
So, weight of 112 mL of oxygen at STP on liquification would be 0.16 g.