$116$ mg of a compound on vaporization in a Victor Meyers apparatus displaces $44.8$ mL of air measured at STP. What is the molecular mass of the compound?

46

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50

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54

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58

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Solution

The correct option is D $58$ g
given, 116 mg of a compound vaporization in victor meyer's apparatus displaces 44.8 ml of air of air measured at stp.
given volume = 44.8ml
so, number of mole of compound = given Volume/22400 ml
= $\frac{44.8 m l}{22400 m l}$
= $\frac{2}{1000}$ = 0.002
we know, no of moles of compound = given weight/molecular weight of compound
so, 0.002 = 116mg/molecular weight of compound
is, molecular weight of compound = $\frac{116 \times 10^{- 3}}{0.002}$
= 58g/mol

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116 mg of a compound on vaporization in a Victor Meyers apparatus displaces 44.8 mL of air measured at STP. What is the molecular mass of the compound?

$116$ mg of a compound on vaporization in a Victor Meyers apparatus displaces $44.8$ mL of air measured at STP. What is the molecular mass of the compound?