Question

118 players are to be divided equally in teams. In what possible way we could group them?

• A. 2 teams
• B. 3 teams
• C. 4 teams
• D. 5 teams

Answer 1

The correct option is A 2 teams

To find the possible way to group 118 players equally in teams, we need to check if 118 is divisible by 2, 3, 4, or 5.

Divisibility rule of 2 is:
If the digit at ones place of a number is even, then the number is divisible by 2.
Observing the division process, we get:


∴ We can group 118 players equally into 2 teams.

Divisibility rule for 3:
If the sum of all the digits of a number is divisible by 3, then the number is divisible by 3.
Observing the division process, we get:


∴ We can't group 118 players equally in 3 teams.

Checking the divisibility rule of 4, we get:
If the last two digits of a number are divisible by 4, then the number is also divisible by 4.
Observing the division process, we get:


∴ We can't group 118 players equally in 4 teams.

Finally, checking the divisibility rule of 5, we get:
If the digit at ones place of a number is 0 or 5, then the number is divisible by 5.
Observing the division process, we get:


∴ We can't group 118 players equally in 5 teams.

Since, 118 is only divisible by 2, hence, 118 players can be grouped equally into only 2 teams.