The given equations are:
11x + 15y + 23 = 0 ........(i)
7x − 2y − 20 = 0 .............(ii)
On multiplying (i) by 2 and (ii) by 15, we get:
22x + 30y + 46 = 0 .......(iii)
105x − 30y − 300 = 0 .......(iv)
On adding (iii) and (iv), we get:
127x = 254
⇒ x = 2
On substituting x = 2 in (i), we get:
22 + 15y + 23 = 0
⇒ 15y = (−23 − 22) = −45
⇒ y = −3
Hence, the solution is x = 2 and y = −3.