(-12) + (12) + (-6) + (-5) + (-7) + (-10) = ___

-28

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+28

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-10

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Solution

The correct option is A
-28

(-12) + (12) + (-6) + (-5) + (-7) + (-10)

= (-12 + 12) - (6 + 5 + 7 + 10)

= 0 - (28)

= -28

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Similar questions

Sum of (-12) + (12) + (-6) + (-5) + (-7) + (-10) is _____.

Q. Find the missing number.

$5$	$6$	$12$	$42$
$7$	$5$	$7$	$42$
$3$	$4$	$10$	$22$
$5$	$?$	$12$	$32$

Simplify: $3 \times \frac{4}{6} + 4 \times \frac{5}{12} - 5 \times \frac{7}{10}$

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

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(-12) + (12) + (-6) + (-5) + (-7) + (-10) = ___

The correct option is A -28 (-12) + (12) + (-6) + (-5) + (-7) + (-10) = (-12 + 12) - (6 + 5 + 7 + 10) = 0 - (28) = -28

The correct option is A
-28

(-12) + (12) + (-6) + (-5) + (-7) + (-10)

= (-12 + 12) - (6 + 5 + 7 + 10)

= 0 - (28)

= -28