12 : 144

22 : 46

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20 : 400

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15 : 135

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10 : 140

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Solution

The correct option is B 20 : 400
The relationship is $x : x^{2}$ .

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Similar questions

\frac{1}{\sqrt{14}} : \frac{1}{2} : \frac{1}{40} : ?

The sum of prime factors of 4620 is:

\frac{1}{\sqrt{\sqrt{12} + \sqrt{140}}} + \frac{1}{\sqrt{8 - \sqrt{60}}} =

12 - \sqrt{140}

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