$12, 15, 19, ?, 30, 37$ .

25

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21

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23

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24

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Solution

The correct option is C $24$
The pattern of the series is as follows.

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21, 21, 22, 23, 23, 24, 24, 24, 24, 25

25

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7^{21} + 7^{22} + 7^{23} + 7^{24}

25

lim n \to \infty \frac{(1^{4} + 2^{4} + 3^{4} + . . . . + (2 n)^{4}) (1^{3 / 2} + 2^{3 / 2} + . . . . + n^{3 / 2})}{(1^{5} + 2^{5} + . . . . + n^{5}) (1^{1 / 2} + 2^{1 / 2} + . . . + n^{1 / 2})}

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