12.2 g of benzoic acid (Mw = 122) in 100 g water has elevation in boiling point of 0.27.Kb=0.54Kkgmol−1. If there is 100% polymerization, the number of molecules of benzoic acid in associated state is
A
2
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B
1
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C
3
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D
4
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Solution
The correct option is A 2 ΔTb=iKbm0.27=i×0.54×12.2122×1000100 or i = 0.5 Therefore, benzene associated as dimer, i.e., 2.