12.5mL of a solution containing 6g of a dibasic acid in 1L was found to be neutralized by 10mL of a decinormal solution of NaOH. The molecular mass of the acid is:
A
110
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B
75
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C
120
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D
150
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Solution
The correct option is D150 N1V1(acid)=N2V2(base) N1×12.5=110×10 N1=112.5 Strength=N×Ew 6=112.5×Ew Ev=75 Molar mass =Equivalentmass×Basicity =75×2=150.