√(√12-√8)(√3+√2)/√(5+√24)

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\frac{\sqrt{(\sqrt{12} - \sqrt{8}) (\sqrt{3} + \sqrt{2})}}{5 + \sqrt{24}}

24 - [12 - {11 - (¯ ¯¯¯¯¯¯¯¯¯¯ ¯ 8 - 5 - 3)}]

Equation of the hyperbola with focus (-3,4) directrix 3x-4y+5=0 and e = $\frac{5}{2}$ is

\frac{3 - 12 x^{2}}{2 x^{2} - 15 x - 8} \times \frac{x^{2} - 5 x - 24}{8 x^{2} - 28 x + 12} .

2^{4} = 16

3^{5} = 243

10^{- 1} = 0.1

8^{- \frac{2}{3}} = \frac{1}{4}

25^{\frac{1}{2}} = 5

12^{- 2} = \frac{1}{144}

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