Question

12.A particle of mass 4gis in a gravitational potential field given by V=(800x²+150)erg/g.Its frequency of oscillation is ---------

Answer 1

$$\begin{gathered} \omega =\sqrt{\frac{V\text{'}\text{'}}{m}} \\ whereV\text{'}\text{'}=\frac{d^{2}V}{d{x}^2}=1600 \\ \omega =\sqrt{\frac{1600}{4}}=20rev/sec \end{gathered}$$