$12$ chairs were arranged with $3$ chairs in each row. Later, $8$ more chairs were added. Find the number of chairs in each row such that the total number of rows remains the same.

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Solution

Initial total number of chairs $= 12$
Number of chairs in each row $= 3$

$∴$ Number of rows $= \frac{12}{3} = 4$

Later, $8$ more chairs were added.
$\Rightarrow 12 + 8 = 20$ chairs.

$Number of chair in each row$
$= \frac{Total number of chairs}{Number of rows} = \frac{20}{4} = 5$

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12 chairs were arranged with 3 chairs in each row. Later, 8 more chairs were added. Find the number of chairs in each row such that the total number of rows remains the same.

Initial total number of chairs =12 Number of chairs in each row =3 ∴ Number of rows =123=4 Later, 8 more chairs were added. ⇒12+8=20 chairs. Number of chair in each row =Total number of chairsNumber of rows=204=5

$12$ chairs were arranged with $3$ chairs in each row. Later, $8$ more chairs were added. Find the number of chairs in each row such that the total number of rows remains the same.

Initial total number of chairs $= 12$
Number of chairs in each row $= 3$

$∴$ Number of rows $= \frac{12}{3} = 4$

Later, $8$ more chairs were added.
$\Rightarrow 12 + 8 = 20$ chairs.

$Number of chair in each row$
$= \frac{Total number of chairs}{Number of rows} = \frac{20}{4} = 5$