12 coins are tossed 4096 times. The number of times that one can get atleast 2 heads is

4080

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4081

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4082

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4083

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Solution

The correct option is A 4080
12 coins are tossed 4096
way to get no head=1
way to get one head=12
way to get at least two heads=total-1-12= $2^{12}$ -13=4096-13=4083

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Three coins are tossed 200 times and we get

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When three coins are tossed at random, what is the probability of getting (i) 3 heads? (ii) 1 head? (iii) 0 head? (iv) 2 heads?

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