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Inverse of Rational Numbers

12. Evaluate ...

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12. Evaluate 15/10+20+40-5-80 Where 5=2.236 and 10=3.162

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Evaluate $\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}}$ , it us given that $\sqrt{5} = 2.236$ and $\sqrt{10} = 3.162$

\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}}

, it being given that

\sqrt{5} = 2.236

\sqrt{10} = 3.162

\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}}

, it being given that

\sqrt{5} = 2.236 and \sqrt{10} = 3.162

\begin{array}{rcl} \frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}} & = & \frac{15}{\sqrt{10} + 2 \sqrt{5} + 2 \sqrt{10} - \sqrt{5} - 4 \sqrt{5}} \\ = & \frac{15}{3 \sqrt{10} - 3 \sqrt{5}} = \frac{5}{\sqrt{10} - \sqrt{5}} \end{array}

\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} + \sqrt{5} - \sqrt{80}}

is being given that

\sqrt{5} = 2.236 a n d \sqrt{10} = 3.162

Q. Evaluate after rationalising the denominator of 25/(√40 - √80) , it being given that √5 = 2.236 and √10 = 3.162

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