$12 g$ $M g$ reacts with a dilute mineral acid to produce maximum hydrogen equal to :

0.5 m o l

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1.5 m o l

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0.75 m o l

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0.35 m o l

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Solution

The correct option is A $0.5 m o l$
$M g + 2 H C l \to M g C l_{2} + H_{2}$
Moles of $M g =$ Moles of $H_{2}$
Moles of $M g = \frac{12}{24} = 0.5 m o l$
So, moles of $H_{2} = 0.5 m o l$
Hence, option $A$ is correct.

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