Question

$12$J of work has to be done against an existing electric field to take a charge of $0.01$C from A to B. How much is the potential difference $V_B-V_A$?

Answer 1

The potential difference is represented as: $V_B-V_A$

The amount of charge $=0.01C$

Work done on the charge to move is $=12$J

Now,the work done is defined as:

$W=V\times q$

$\Rightarrow$ Pot. Diff$=\frac{12}{0.01}=1200$Volt.