Question

$12$ L of $H_2$ and $11.2$ L of $C{l}_2$ are mixed and exploded. The composition by volume of mixture is :

• A. $24$ L of $HCl$ (g)
• B. $0.8$ L $C{l}_2$ and $20.8$ L $HCl$ (g)
• C. $0.8$ L $H_2$ and $22.4$ L $HCl$ (g)
• D. $22.4$ L $HCl$ (g)

Answer 1

The correct option is C $0.8$ L $H_2$ and $22.4$ L $HCl$ (g)

$12$ L of $H_2$ and $11.2$ L of $C{l}_2$ are mixed and exploded.

The composition by volume of mixture is $0.8$ L $H_2$ and $22.4$ L $HCl$ (g).

The balanced equation is:

$H_2+C{l}_2\to 2HCl$

11.2 L of hydrogen will react with 11.2 L of chlorine to produce $2\times 11.2=22.4$ L of HCl,

$12-11.2=0.8$ L of hydrogen will remain unreacted.