CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Full Wave Rectifier

12 signals ea...

Question

12 signals each band limited to $5 k H z$ are to be transmitted by frequency-division multiplexer. If AM-SSB modulation guard band of $1 k H z$ is used then the bandwidth of multiplexed signal is

A

101 k H z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

99 k H z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

84 k H z

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

71 k H z

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $71 k H z$
Total signal B.W $= 12 \times 5 = 60 k H z$
11 guard band are required between 12 signal.
$∴$ Guard bandwidth $= 11 \times 1 k H z = 11 k H z$
$∴$ Total bandwidth $60 + 11 = 71 k H z$

Suggest Corrections

thumbs-up

0

Similar questions

Q. 4 Voice signals, each with a bandwidth of 4 kHz, are to be transmitted through a baseband channel using time division multiplexing. If the signals are sampled at Nyquist rate and quantized with an 8-bit quantizer, then the theoretical minimum channel bandwidth required to transmit the multiplexed signal is used to

Q. The spectrum in the range (550 to 1650) kHz is allocated for AM radio broadcasting and the spectrum is shared for different AM radio stations using frequency division multiplexing (FDM). If the message signal of each AM radio station is band-limited to 5 kHz then the maximum number of different AM radio stations that can be enjoyed by a listener will be equal to

Q. In a certain telemetry system, there are four analog signals, in which one signal is bandlimited to 3.6 kHz and the remaining three signals are bandlimited to 1.5 kHz. If these signals are transmitted through an 8-bit PCM system using time division multiplexing, then the minimum channel bandwidth required will be __________kHz.

Q. An audio signal consists of two distinct sounds : one a human speech signal in the frequency band of

200 H z

2700 H z

, while the other is a high frequency music signal in the frequency band of

10200 H z

15200 H z

. The ratio of the AM signal bandwidth required to send both the signals together to the AM signal bandwidth required to send just the human speed is:

Q. The message signal is used to SSB-SC modulate a sinusoidal carrier signal. If

f_{\infty} = 2 k H z,

then the bandwidth of the resultant modulated signal will be ____kHz.

m (t) = {[\frac{s i n (2 π f_{m} t)}{π f_{m} t}]}^{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Full Wave Rectifier

PHYSICS

Watch in App

explore_more_icon

Explore more

Full Wave Rectifier

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon