Question

$12\text{g}$ $\text{He}$ and $4\text{g}{\text{H}}_2$ filled in a container of volume $20\text{L}$ maintained at temperature $300\text{K}$. The pressure of the mixture is nearly

• A. $3.225\text{atm}$
• B. $5.225\text{atm}$
• C. $6.225\text{atm}$
• D. $1.225\text{atm}$

Answer 1

The correct option is C $6.225\text{atm}$

We know that, ideal gas equation is,
$PV=nRT=\frac{m}{M}RT$
For $\text{He}$,
$P_{\text{He}}=\frac{12}{4\times 20}\times 0.083\times 300=3.735\text{atm}$
Similarly,
For ${\text{H}}_2$,
$P_{{\text{H}}_2}=\frac{4}{2\times 20}\times 0.083\times 300=2.490\text{atm}$
So, Total pressure of non-reactive gas,
$P=P_{\text{He}}+P_{{\text{H}}_2}=3.735+2.490=6.225\text{atm}$