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Perpendicular to a Line

12. The image...

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12. The image of the circle s1=x2+y2=25 with respect to the line y=1 is represented by

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Q. The equation of the image of the circle

x^{2} + y^{2} - 6 x - 4 y + 12 = 0

by the line mirror

x + y - 1 = 0

Q. Find the pole of the straight line 2x + y + 12 = 0 with respect to the circle

x^{2} + y^{2} - 4 x + 3 y - 1 = 0 .

Q. The image of the circle

x^{2} + y^{2} = 16

x + y = 4

Q. The image of the circle

x^{2} + y^{2} - 2 x = 0

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Q. For the circles

S_{1} \equiv x^{2} + y^{2} - 4 x - 6 y - 12 = 0

S_{2} \equiv x^{2} + y^{2} + 6 x + 4 y - 12 = 0

L \equiv x + y = 0

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Perpendicular to a Line

Standard VI Mathematics