12×(2−13)×(2−35)×(2−57)×(2−79)×(2−911)………(2−997999)×(12002) = ?
1001
4
1
2
None of these
12×53×75×97×119×1311………1001999×(12002)
=123×10012002=2
Fill in the blanks:
(i) −4×79=79× ___
(ii) 511×−38=−38× ___
(iii) 12×(34+−512)=12× ____ +(×)−512
(iv) −45×57×___ =(−45×57)×−89
Evaluate :
(i) 37+−49+−117+79(ii) 23+−45+13+25(iii) 47+0+−89+−137+179(iv) 38+−512+37+312+−58+−27
Re-arrange suitably and find the sum in each of the following :
(i)1112+−173+112+−252
(ii)−67+−56+−49+−157
(iii)35+73+95+−1315+−73
(iv) 413+−58+−813+913
(v)23+−45+13+25
(vi) 18+512+27+712+97+−516