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Discovery of Electrons

12) Two point...

Question

12) Two point charges q₁ and q₂ are at distance 3 m. The sum of these charges is 20 $μ C$ . If a charge repels the other with a force of 0.075 N. Then calculate the value of both the charges.
$(A n s w e r : 15 μ C a n d 5 μ C)$

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Solution

Dear Student,
$A c c o r d i n g t o q u e s t i o n K \frac{q_{1} q_{2}}{3^{2}} = . 075 q_{1} q_{2} = \frac{. 075 \times 9}{9 \times 10^{9}} = 75 \times 10^{- 12} b u t q_{1} + q_{2} = 20 \times 10^{- 6} C - - - 1 q_{1} - q_{2} = \sqrt{{(q_{1} + q_{2})}^{2} - 4 q_{1} q_{2}} = \sqrt{400 \times 10^{- 12} - 300 \times 10^{- 12}} = 10^{- 6} q_{1} - q_{2} = 10 \times 10^{- 6} C - - - 2 a f t e r s o l v o n g 1 a n d 2 w e g e t q_{1} = 15 μ C a n d q_{2} = 5 μ C$
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