1200 c of oxygen was burnt with 400 cc of Methane $(C H_{4})$ . Calculate the volume of unused oxygen left, after writing the balanced equation.

Methane + Oxygen $\to$ Carbon dioxide + Water vapour

20 cc

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400 cc

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200 cc

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800 cc

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Solution

The correct option is B
400 cc

$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$

400

1 volume of $C H_{4}$ needs 2 volumes of $O_{2}$

$∴$ 400 cc of $C H_{4}$ needs $\frac{2}{1} \times 400 = 800 c c$ \)

$∴$ Volume of $O_{2}$ unused = 1200 - 800

= 400 cc

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1200 c of oxygen was burnt with 400 cc of Methane (CH4). Calculate the volume of unused oxygen left, after writing the balanced equation. Methane + Oxygen → Carbon dioxide + Water vapour

The correct option is B 400 cc CH4+2O2→CO2+2H2O 400 1 volume of CH4 needs 2 volumes of O2 ∴ 400 cc of CH4 needs 21×400=800 cc\) ∴ Volume of O2 unused = 1200 - 800 = 400 cc

1200 c of oxygen was burnt with 400 cc of Methane $(C H_{4})$ . Calculate the volume of unused oxygen left, after writing the balanced equation.

Methane + Oxygen $\to$ Carbon dioxide + Water vapour

The correct option is B
400 cc

$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$

400

1 volume of $C H_{4}$ needs 2 volumes of $O_{2}$

$∴$ 400 cc of $C H_{4}$ needs $\frac{2}{1} \times 400 = 800 c c$ \)

$∴$ Volume of $O_{2}$ unused = 1200 - 800

= 400 cc