1200 men can finish a stock of food in 35 days. How many more men should join them so that the same stock may last for 25 days ?

Open in App

Solution

Let x men can finish the stock, then
$\begin{matrix} Men & 1200 & x Period (in days) & 35 & 25 \end{matrix}$
Less period, More men
$∴$ By inverse variation
$1200 : x = 25 : 35 \Rightarrow \frac{1200}{x} = \frac{25}{35} \Rightarrow x \times 25 = 35 \times 1200 \Rightarrow x = \frac{35 \times 1200}{25} = 1680$
Already men working = 1200
$∴$ More men required = 1680-1200=480

Suggest Corrections

Similar questions

1200

men can finish the stock of food in

35

days. How many more men should join them so that the same stock of food may last

25

days?

10 men can reap a field in 20 days. 10 men reaped the field for 10 days and after 10 days 10 more men join them. In how many days will the work be finished?

Q. If

15

men can do a piece of work in

20

days. In how many days can

25

men finish the same work?

Q. 10 men can finish a job in 10 days. In how many days 20 men can finish the same job?

Q. A military camp has provision for 63 men to least for 25 days. How many men must be transfered to another camp so that the food lasts for 30 days?

Join BYJU'S Learning Program

1200 men can finish a stock of food in 35 days. How many more men should join them so that the same stock may last for 25 days ?

Let x men can finish the stock, then Men1200xPeriod (in days)3525 Less period, More men ∴ By inverse variation 1200:x=25:35⇒1200x=2535⇒x×25=35×1200⇒x=35×120025=1680 Already men working = 1200 ∴ More men required = 1680-1200=480