(123+5.6)−3.6 equals
125
We know that (x+y)−z=x+(y−z), for all numbers x, y, z with y>z.
Since the above is true for all the numbers, it must be true for x=123, y=5.6 and z=3.6 also, as y=5.6>3.6=z
So, (123+5.6)−3.6 = 123+(5.6−3.6) = 123+2 = 125