$(123)_{5} = (x)_{10}$ . Then $x =$ ?

19

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39

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26

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38

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Solution

The correct option is D $38$
25 $(5^{2})$ 5 $(5^{1})$ 1 $(5^{0})$
1 2 3
25x1 5x2 3x1
Number in decimal form will be 25x1+5x2+3x1=25+10+3=38
So correct answer will be option D

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\frac{- 39}{3} \times \frac{19}{5} \times \frac{- 45}{38}

∣ ∣ ∣ ∣ \begin{matrix} 67 & 19 & 21 39 & 13 & 14 81 & 24 & 26 \end{matrix} ∣ ∣ ∣ ∣

_{18} A r^{38}

City	Average maximum temperature	Average minimum temperature
New Delhi	$39^{o} C$	$27^{o}$
Mumbai	$36^{o} C$	$19^{o} C$
Ahemdabad	$37^{o} C$	$19^{o} C$
Chennai	$42^{o} C$	$26^{o} C$
Kolkata	$38^{o} C$	$24^{o} C$

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