125 mL of 10% NaOH (w/V) is added to 125 mL of 10% HCl (w/V). The resultant solution becomes:
A
alkaline
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B
strongly alkaline
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C
acidic
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D
neutral
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Solution
The correct option is B neutral The answer is neutral because NaOH is a strong base and HCl is a strong acid.When a strong acid is added to strong base,the solution because neutral.