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Trigonometric Ratios of Multiples of an Angle

125. Sin (A+B...

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125. Sin (A+B)=1 and cos (A-B) =1 then find out values of A andB

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Q. If cosec (A + B) = 1 and cosec(A – B) = 2, 0° < (A + B) ≤ 90° and A > B then find the values of :
(i) sin A cos B + cos A sin B
(ii)

\frac{\tan A - \tan B}{1 + \tan A \tan B}

sin (A - B) = \frac{1}{2}, cos (A + B) = \frac{1}{2}

0^{\circ} < A + B < 90^{\circ}, A > B

, then find the values of

A

B

.

tan A = \frac{x sin B}{1 - x cos B}

tan B = \frac{y sin A}{1 - y cos A}

, then the value of

\frac{sin A}{sin B}

for all permissible values of

A, B

If 2 cos(A + B) = 1, and 2 sin(A –B) = 1 then the values of A and B are

sin A sin B - cos A cos B + 1 = 0

, then the value of

1 - cot A tan B

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Trigonometric Ratios of Multiples of an Angle

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