Question

${127.83}^{\circ }$ is equivalent to

• A. ${127}^{\circ }{47}^{\prime }{48}^{\prime \prime }$
• B. ${127}^{\circ }{49}^{\prime }{18}^{\prime \prime }$
• C. ${127}^{\circ }{45}^{\prime }{48}^{\prime \prime }$
• D. ${127}^{\circ }{49}^{\prime }{48}^{\prime \prime }$

Answer 1

The correct option is D ${127}^{\circ }{49}^{\prime }{48}^{\prime \prime }$

${127.83}^{\circ }={127}^{\circ }+{0.83}^{\circ }$
Now,
${0.83}^{\circ }=(0.83\times 60{)}^{\prime }={49.8}^{\prime }={49}^{\prime }+{0.8}^{\prime }$
Now,
${0.8}^{\prime }=(0.8\times 60{)}^{\prime \prime }={48}^{\prime \prime }$

$\therefore {127.83}^{\circ }={127}^{\circ }{49}^{\prime }{48}^{\prime \prime }$