127 - 8 -101 - 5-19 - 4 -41 - 8-

The correct option is C 345 16×20+5×5 = 320+25 = 345 ...

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Byju's Answer

Standard VII

Mathematics

Division of Integers

127 ÷ 8 ×101 ...

Question

$(127 \div 8) \times (101 \div 5) + (19 \div 4) \times (41 \div 8) = ?$

300

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325

No worries! We‘ve got your back. Try BYJU‘S free classes today!

345

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365

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375

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Solution

The correct option is C
345

16 $\times$ 20+5 $\times$ 5 = 320+25 = 345

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Similar questions

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Q. 8. (101)4

Use the sign of >, < or = in the box to make the statements true.

(i) Evaluate:

$(a) (- 2) \times (- 3) \times (- 4)$

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(ii) Use the sign of >, < or = in the box to make the statements true.

$(a) (- 8) + (- 4) □ (- 8) + (- 4)$

$(b) (- 3) + 7 - (19) □ 15 - 8 + (- 9)$

$(c) 23 - 41 + 11 □ 23 - 41 - 11$ [3 MARKS]

Simplify the following

(a) 12 + [{1 + (15 − 3)} × 4]

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(c)

(d)

(e)

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(127÷8)×(101÷5)+(19÷4)×(41÷8)=?

The correct option is C 345 16×20+5×5 = 320+25 = 345

$(127 \div 8) \times (101 \div 5) + (19 \div 4) \times (41 \div 8) = ?$

The correct option is C
345

16 $\times$ 20+5 $\times$ 5 = 320+25 = 345