127- The total spin resulting from d9 nbsp-configuration is i- 9-2 ii- 2 iii- 5-2 iv- 1-2

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Shielding Effect

127. The tota...

Question

127. The total spin resulting from d⁹ configuration is
i) 9/2
ii) 2
iii) 5/2
iv) 1/2

Open in App

Solution

Dear student,

In the case of d sub-shells as it has 5 orbitals and each will accommodate 2 electrons.
In, $d^{9}$ the number of unpaired electrons = 1
The total spin value is $\frac{n}{2}$ where, n = number of unpaired electrons ( n=1)
For, $d^{9}$ the total value of spin is $\frac{1}{2}$

Regards

Suggest Corrections

Similar questions

Q. The total spin resulting from

d^{7}

electronic configuration is;

Arrange the elements with the following electronic configurations in the increasing order of electron affinity

(i) $1 s^{2} 2 s^{2} 2 p^{3}$ (ii) $1 s^{2} 2 s^{2} 2 p^{4}$ (iii) $1 s^{2} 2 s^{2} 2 p^{5}$ (iv) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}$

Q. Consider the following statements:
(I) Rutherford name was associated with the development of periodic table.
(II) A metal M having electronic configuration

1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1}

is d-block element.
(III) Diamond is not an element.
(IV) The electronic configuration of the most electronegative element is

1 s^{2}, 2 s^{2}, 2 p^{5}

Select the correct option from the given codes.

Q. The total spin resulting from a

d^{9}

configuration is :

Evaluate :

$(i) (- 5)^{\circ} (i i) 8^{\circ} + 4^{\circ} + 2^{\circ} (i i i) (8 + 4 + 2)^{\circ} (i v) 4 x^{\circ} (v) (4 x)^{\circ} (v i) [(10^{3})^{\circ}]^{5} (v i i) (7 x^{\circ})^{2} (v i i i) 9^{\circ} + 9^{- 1} - 9^{- 2} + 9^{\frac{1}{2}} - 9^{- \frac{1}{2}}$

Join BYJU'S Learning Program

127. The total spin resulting from d9 configuration is i) 9/2 ii) 2 iii) 5/2 iv) 1/2

Dear student, In the case of d sub-shells as it has 5 orbitals and each will accommodate 2 electrons. In, d9 the number of unpaired electrons = 1 The total spin value is n2 where, n = number of unpaired electrons ( n=1) For, d9 the total value of spin is 12 Regards

127. The total spin resulting from d⁹ configuration is
i) 9/2
ii) 2
iii) 5/2
iv) 1/2

Dear student,

In the case of d sub-shells as it has 5 orbitals and each will accommodate 2 electrons.
In, $d^{9}$ the number of unpaired electrons = 1
The total spin value is $\frac{n}{2}$ where, n = number of unpaired electrons ( n=1)
For, $d^{9}$ the total value of spin is $\frac{1}{2}$

Regards